Given :
The CHS basketball team scored a total of 70 points in their last game. They made 25 total shots. Some of the shots were worth two points and some of the shots were three-pointers.
To Find :
A system of equations to model the situation.
Solution :
Let, number of two pointer shots are x and three pointers are y.
So, x + y = 25 .......1)
Total points scored , S = 70.
[tex]2x+3y=70[/tex] .......2)
Solving equation 1 and 2 , we get :
[tex]2x+3(25-x)=70\\\\x=5[/tex]
y = 25 - 5 =20
Therefore, total numbers of two and three pointers are 5 and 20 respectively.
Hence, this is the required solution.
