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Find the inverse function (find f^-1)
[tex]f(x)=\frac{x-2}{3x+3}[/tex]

I have the correct answer, I just don't know how to get to it.
answer is: [tex]f^{-1} =\frac{-2-3x}{3x-1}[/tex]

Respuesta :

ChoiSungHyun

Step-by-step explanation:

f(x) = (x-2)/(3x+3). Let y = f(x).

Then y = (x-2)/(3x+3).

y(3x+3) = x - 2

3xy + 3y = x - 2

3xy - x = -3y - 2

x(3y-1) = -(3y+2)

x = -(3y+2)/(3y-1)

Hence, the inverse of f(x) is -(3x+2)/(3x-1).

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