Mr. Nelson lost one of his students' test

papers. He knows that the other 4 students

scored as follows: 60, 62, 56, 57. He also

knows that the average score is 59.2.

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Complete question :

Mr. Nelson lost one of his students' test papers. He knows that the other 4 students scored as follows: 60, 62, 56, 57. He also knows that the average score is 59.2. What is the score on the missing paper?

Answer:

61

Step-by-step explanation:

Given the following :

Total number of students = 4 + 1 missing = 5

Score on the four avaliable papers = 60, 62, 56, 57

Average score of the 5 papers = 59.2

Score on missing paper :

Sum of each score / number of papers

Sum of each score = sum of available scores + missing score

Let missing score = m

(60 + 62 + 56 + 57 + m) = 235 + m

Recall:

Average = total sum / number of observations

Hence,

59.2 = (235 + m) / 5

59.2 × 5 = 235 + m

296 = 235 + m

m = 296 - 235

m = 61

Missing score = 61

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