It take "1.49 sec" to hit the moon's surface. A further explanation is provided below.
According to the question,
Height,
Acceleration of gravity,
Initial velocity,
With the help of the equation,
→ [tex]t^2 = \frac{2d}{a}[/tex]
By substituting the values, we get
→ [tex]= \frac{2\times 1.2}{1.62}[/tex]
→ [tex]= \frac{2.4}{1.62}[/tex]
→ [tex]= 1.49 \ sec[/tex]
Thus the above answer is right.
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