Answer:
Diffusive force J = 9590
Explanation:
From the given information:
Concentration gradient C₁ - C₂ = 35 mM = 35 × 10⁻³ M
membrane width Δ x = 1 cm = 10⁻² m
Solubility S = 1
diffusive area A = 10
Temperature T = 1° C = (273 + 1 )K = 274 K
Using the expression:
[tex]\text {diffusive force J} = \dfrac{C_1-C_2}{\Delta x }\times T \times S \times A[/tex]
[tex]J = \dfrac{35 \times 10^{-3}}{10^{-2} }\times 274 \times 1 \times 10[/tex]
[tex]J = 3.5 \times 274 \times 1 \times 10[/tex]
Diffusive force J = 9590
