Explanation:
(a) The total energy is the elastic potential energy at maximum displacement.
E = ½ kx²
E = ½ (40.0 N/m) (0.0500 m)²
E = 0.05 J
(b) At this displacement, there is both elastic potential energy and kinetic energy.
E = EE + KE
0.05 J = ½ kx² + ½ mv²
0.05 J = ½ (40.0 N/m) (0.0200 m)² + ½ (0.060 kg) v²
v = 1.18 m/s
(c) E = EE + KE
0.05 J = ½ kx² + ½ mv²
0.05 J = ½ (40.0 N/m) (0.0250 m)² + KE
KE = 0.0375 J
(d) EE = ½ kx²
EE = ½ (40.0 N/m) (0.0250 m)²
EE = 0.0125 J
