Answer: 504 ways
Step-by-step explanation:
given data:
no of people = 6
no of offices = 3
no of people in each office = 2
solution:
first we need to find the number of ways 6 people can be shared in 2 or pairs as this is a combination problem.
= 6C2
= 15 ways
ways to place a pair of 2 in 3 offices
= 15 * 3
= 45ways.
using the remaining 4 people we have 4C2 = 6 ways
in the remaining 2 offices
6 * 2 = 12ways
withour conditions
= 45 * 12
= 540ways
considering the constraint
= 4C2
= 6ways
shared in 3 offices
= 6 * 3
= 18 ways
remaining 2 offices
= 18 * 2
= 36 ways
Without constraints - With constraints
= 540 - 36
= 504ways
90 ways.
Given:
Six people are to be assigned in three offices, two people per office.
Thinking of this problem from the perspective of offices themselves picking persons, we get this:
Firstly out of 6 person, 2 person are chosen in [tex]^6C_2[/tex] ways.
Secondly, from rest of the 4 persons, 2 people are chosen in [tex]^4C_2[/tex] ways.
Then rest of the 2 persons are chosen from rest persons in [tex]^2C_2[/tex] ways.
Applying law of multiplication for number of ways:
Total number of ways = [tex]^6C_2 \times ^4C_2 \times ^2C_2 = 15 \times 6 \times 1 = 90[/tex]
For more information, refer this link below:
https://brainly.com/question/13003667
