Hello, we know that
[tex]|x|=\begin{cases}x &\text{if } x \geq 0\\ -x &\text{if } x < 0 \end{cases}[/tex]
And we can write that 12x-5=0 <=> 12x =5 <=> x = 5/12
So,
[tex]|12x-5|=\begin{cases}12x-5 &\text{if } x \geq \dfrac{5}{12}\\\\ -12x+5 &\text{if } x < \dfrac{5}{12}\end{cases}[/tex]
And, we can write.
[tex]|12x-5|=11<=>\begin{cases}12x-5=11 &\text{if } x \geq \dfrac{5}{12}\\\\ -12x+5=11 &\text{if } x < \dfrac{5}{12}\end{cases}\\ \\ \\ <=>\begin{cases}12x=16 &\text{if } x \geq \dfrac{5}{12}\\\\ 12x=5-11 &\text{if } x < \dfrac{5}{12}\end{cases}\\\\<=>\begin{cases}x=\dfrac{16}{12}=\boxed{\dfrac{4}{3}} &\text{if } x \geq \dfrac{5}{12}\\\\ x=\dfrac{-6}{12}=\boxed{-\dfrac{1}{2}} &\text{if } x < \dfrac{5}{12}\end{cases}[/tex]
So the two solutions are 4/3 and -1/2.
Thank you.
