Answer:
The work function is [tex]\phi = 2.46 \ eV[/tex]
Explanation:
From the question we are told that
The light energy is [tex]E = 3.56 eV[/tex]
The stopping voltage is [tex]V = 1.10 \ V[/tex]
Generally work function is mathematically represented as
[tex]\phi = E - KE[/tex]
Where KE is the kinetic energy of the ejected electron and it is mathematically represented as
[tex]KE = V * e[/tex]
Where e is the charge on the electron
So
[tex]KE = 1.10eV[/tex]
Thus
[tex]\phi = 3.56eV - 1.10 eV[/tex]
=> [tex]\phi = 2.46 \ eV[/tex]
