The formula for the size of a file that was downloaded over time t and at an average rate r is r.t.
Siena downloaded a file at a rate of 800 kilobytes per second for about 110 seconds.
What calculation will give us the estimated size of the file Siena downloaded, in megabytes?

Respuesta :

Answer:

The size of file downloaded is  88 megabytes.

Step-by-step explanation:

Given that:

Average rate of downloading the file = [tex]r[/tex]

Time taken to download = [tex]t[/tex]

Formula for the size of file downloaded = [tex]r.t[/tex]

Rate of downloading, [tex]r = 800\ kilobytes/sec[/tex]

Time taken, [tex]t[/tex] = 110 seconds

To find:

Size of file downloaded in megabytes = ?

Solution:

First of all, let us apply the given formula to find the size of file downloaded:

Size of file downloaded = [tex]r.t[/tex]

Size of file downloaded = 800 kilobytes seconds [tex]\times[/tex] 110 seconds =

88000 kilobytes.

Now, let us convert the unit kilobytes to megabytes to find the answer.

Conversion formula:

1000 kilobytes = 1 megabyte

Let us use unitary method to find the number of megabytes in 88000 kilobytes.

1 kilobytes = [tex]\frac{1}{1000}[/tex] megabytes

88000 kilobytes = [tex]\frac{1}{1000} \times[/tex] 88000 megabytes

[tex]\Rightarrow[/tex] 88 megabytes.

Therefore, the size of file downloaded is  88 megabytes.

Answer:

800/1000*110

Step-by-step explanation:

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