Respuesta :

sebassandin

Answer:

[tex]\%m/m=0.15\%[/tex]

Explanation:

Hello,

In this case, we are asked to compute the by mass percent representing the toxicity of ethylene glycol in the body mass. In such a way, since the by mass percent is computed as follows:

[tex]\%m/m=\frac{m_{solute}}{m_{solute}+m_{solvent}} *100\%[/tex]

Whereas the solute is the ethylene glycol in the body mass, we obtain:

[tex]\%m/m=\frac{1.5g}{1.5g+1000g} *100\%\\\\\%m/m=0.15\%[/tex]

Best regards.

Oseni

The percentage of ethylene glycol that is fatal would be 0.15%.

The toxic quantity is 1.5 g of ethylene glycol for 1000 g of body mass.

The percentage toxic quantity in relation to the body mass can be calculated as:

Percentage = mass of toxic quantity/body mass x 100%

                    = 1.5/1000 x 100%

                       = 0.15 %

Thus, the fatal level of ethylene glycol is 0.15% of body mass.

More on calculating percentages can be found here: https://brainly.com/question/1497956?referrer=searchResults

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