Answer:
0.742M is the concentration of ClO₃⁻
Explanation:
The AgClO₃ contains 1 mole of ClO₃⁻ per mole of compound, but Mn(ClO₃)₂ contains 2 moles of ClO₃⁻ per mole of compound.
The moles of AgClO₃ are:
0.967L * (0.367moles / L) = 0.355 moles AgClO₃ = 0.355 moles of ClO₃⁻
And of Mn(ClO₃)₂:
0.667L * (0.643moles / L) = 0.429 moles Mn(ClO₃) * 2 = 0.858 moles of ClO₃⁻
That means total moles of ClO₃⁻ are:
0.355 moles + 0.858 moles = 1.213 moles ClO₃⁻ that are in 0.967L + 0.667L = 1.634L.
The concentration is:
1.213 moles ClO₃⁻ / 1.634L =
0.742M is the concentration of ClO₃⁻
