Answer:
The change in temperature is [tex]26.06^{\circ} C[/tex].
Explanation:
It is given that,
The specific heat of Aluminium is cal/g°C
Mass of the sample, m = 4.55 g
Heat absorbed, Q = 2.55 cal
We need to find the change in temperature of the sample. The heat absorbed by an object is given by :
[tex]Q=mc\Delta T[/tex]
[tex]\Delta T[/tex] is the change in temperature
So,
[tex]\Delta T=\dfrac{Q}{mc}\\\\\Delta T=\dfrac{2.55\ cal}{4.55\ g\times 0.0215 \ cal/g^{\circ} C}\\\\\Delta T=26.06^{\circ} C[/tex]
So, the change in temperature is [tex]26.06^{\circ} C[/tex].
