Answer:
The pressure is [tex]P_f = 0.93 \ atm[/tex]
Explanation:
From the question we are told that
The volume of Ne is [tex]V_N = 2.50 \ L[/tex]
The volume of CO is [tex]V_C = 2.00 \ L[/tex]
The pressure of [tex]Ne[/tex] is [tex]P_N = 1.09 \ atm[/tex]
The pressure of CO is [tex]P_C = 0.773 \ atm[/tex]
The number of moles of Ne present is evaluated using the ideal gas equation as
[tex]n_N = \frac{P_N * V_N}{R T}[/tex]
=> [tex]n_N = \frac{1.09 * 2.50 }{R T} = \frac{2.725}{RT}[/tex]
The number of moles of CO present is evaluated using the ideal gas equation as
[tex]n_N = \frac{P_C * V_C}{R T}[/tex]
=> [tex]n_N = \frac{0.73 * 2.00 }{R T} = \frac{1.46}{RT}[/tex]
The total number of moles of gas present is evaluated as
[tex]n_T = n_N + n_C[/tex]
[tex]n_T = \frac{2.725}{RT} + \frac{1.46}{RT}[/tex]
[tex]n_T = \frac{4.185}{RT}[/tex]
The total volume of gas present when valve is opened is mathematically represented as
[tex]V_T = V_N + V_C[/tex]
=> [tex]V_T = 2.50 + 2.00 = 4.50 \ L[/tex]
So
From the ideal gas equation the final pressure inside the system is mathematically represented as
[tex]P_f = \frac{n_T * RT }{ V_T}[/tex]
=> [tex]P_f = \frac{[\frac{4.185}{RT} ] * RT }{ 4.50}[/tex]
=> [tex]P_f = 0.93 \ atm[/tex]
