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What entropy change is associated with the reversible phase change from 1.0kg of ice to water at 0 ° C?

Respuesta :

znk

Answer:

1200 J/K  

Explanation:

The formula for the entropy associated with a reversible phase change is

[tex]\Delta S= \dfrac{q_{\text{rev}}}{T}[/tex]

For a reversible phase change like melting,

[tex]q_{\text{rev}} = m\Delta_{\text{fus}}H[/tex]

Data:

Mass of ice = 1.0 kg

T = 0 °C

Calculations

1. Convert the mass of ice to grams

[tex]\text{Mass of ice} = \text{1.0 kg } \times \dfrac{\text{1000 g}}{\text{1 kg}} = \text{1000 g}[/tex]

2. Convert the temperature to kelvins

T = (0 + 273.15) K = 273.15 K

3. Calculate the heat needed to melt the ice

[tex]q_{\text{rev}} = m\Delta_{\text{fus}}H = \text{1000 g} \times \dfrac{\text{334 J}}{\text{1 g}} = \text{334 000 J}[/tex]

4. Calculate the entropy change

[tex]\Delta S = \dfrac{q_{\text{rev}}}{T} = \dfrac{\text{334 000 J}}{\text{273.15 K}} = \textbf{1200 J/K}[/tex]

 

Answer:

Never gonna give you up

Never gonna let you down

Never gonna run around and desert you

Never gonna make you cry

Never gonna say goodbye

Never gonna tell a lie and hurt you

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