Answer:
The z-score of a bag containing 178 peanuts is -2.03.
Step-by-step explanation:
A z-score is a normally distributed value with mean 0 and standard deviation 1. The distribution of these z-scores is known as the standard normal distribution.
The formula to compute z-score is:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
The information provided is:
x = 178
μ = 184.7
σ = 3.3
Compute the z-score of a bag containing 178 peanuts as follows:
[tex]z=\frac{x-\mu}{\sigma}[/tex]
[tex]=\frac{178-184.7}{3.3}\\\\=-2.03[/tex]
Thus, the z-score of a bag containing 178 peanuts is -2.03.
