Answer:
answer B: (2,-2)
Step-by-step explanation:
First, write the equations on top of each other:
[tex]3x+2y=2\\2x-y=6[/tex]
Then, multiply the the second equation by 2 so that we can use elimination of the y-variable:
[tex]3x+2y=2\\2(2x-y)=2(6)\\\\3x+2y=2\\4x-2y=12[/tex]
Next, use elimination to find the value of "x":
[tex]3x+2y=2\\+(4x-2y=12)\\\\7x+0=14\\7x=14\\\frac{7x}{7}=\frac{14}{7}\\x=2[/tex]
So, your x-value is 2.
Now, substitute your x-value into one of your equations, let's take the second equation, 2x-y=6:
[tex]2x-y=6\\2(2)-y=6\\4-y=6\\4-4-y=6-4\\-y=2\\\frac{-y}{1}=\frac{2}{-1}\\y=-2[/tex]
Your y-value is -2.
With all your information gathered, you find that the solution to this system of equation is (2,-2).
