Answer:
we have 8 quarts of 40% antifreeze,
according to the britain equivalent, 1 quart = 1.13L
so, we have 8 * 1.13L = 9.04 L
out of the 9.04 L, 40% is antifreeze
amount of antifreeze = 0.4 * 9.04 = 3.616 L
moles of antifreeze present = 3.616/22.4 = 0.16 moles
moles of antifreeze in 60% solution = 0.6 * v/22.4 = 0.027 * v
(where v is the volume of final solution)
molarity of initial solution = 0.16/9.04 = 0.018 M
molarity of final solution = 0.027*v/v = 0.027 M
m1*v1 = m2*v2
0.018 * 9.04 = 0.027 * v
v = 0.018 * 9.04/0.027
v = 6.026 L
amount if antifreeze in the final solution = 6.026 * 0.027 =
0.163 Moles of antifreeze
amount in L = 0.163 * 22.4 = 3.65 L
amount in quarts = 3.65/1.13 = 3.23 quarts
