Answer: 206
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Work Shown:
a = 3/4
b = -8
c = -2
d = 3
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c-d = -2-3 = -5
(c-d)^2 = (-5)^2 = 25
a+(c-d)^2 = 3/4 + 25 = 3/4 + 100/4 = 103/4
-b * [ a + (c-d)^2 ] = -(-8)*103/4 = 8*103/4 = (8/4)*103 = 2*103 = 206
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Another way to show the steps could be
[tex]-b[a+(c-d)^2]\\\\-(-8)\left[\frac{3}{4}+(-2-3)^2\right]\\\\8\left[\frac{3}{4}+(-5)^2\right]\\\\8\left(\frac{3}{4}+25\right)\\\\8\left(\frac{3}{4}+\frac{100}{4}\right)\\\\8\left(\frac{3+100}{4}\right)\\\\8\left(\frac{103}{4}\right)\\\\\frac{8}{4}*103\\\\2*103\\\\206\\\\[/tex]
Which is more or less the same thing as the previous section.
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So ultimately,
[tex]-b[a+(c-d)^2] = 206[/tex]
when a = 3/4, b = -8, c = -2, and d = 3.
