Answer:
(a) -5, 4
(b) no solution
Step-by-step explanation:
(a) x+5 will be zero when x = -5.
x-4 will be zero when x = 4.
The restricted values are: x = -5 and x = 4.
__
(b) We can simplify the difference of the two sides of the equation.
[tex]\dfrac{4}{x+5}+\dfrac{5}{x-4}=\dfrac{45}{(x+5)(x-4)}\\\\\dfrac{4(x-4)+5(x+5)}{(x+5)(x-4)}=\dfrac{45}{(x+5)(x-4)}\\\\\dfrac{9x+9}{(x+5)(x-4)}-\dfrac{45}{(x+5)(x-4)}=0\\\\\dfrac{9(x-4)}{(x+5)(x-4)}=0\\\\\dfrac{9}{x+5}=0\qquad\text{NO SOLUTION}[/tex]
__
The graph shows there are no values of x that cause the two sides of the equation to be equal (their difference to be zero).
