The data show the number of hours of television watched per day by a sample of people. Use technology to answer parts​ (a) and​ (b) below. a. Find the data​ set's first,​ second, and third quartiles. nothing nothing nothing ​(Type integers or decimals. Do not​ round.) b. Draw a​ box-and-whisker plot that represents the data set. Choose the answer below. Note that different technologies will produce slightly different results. A. 0 3 6 9 A boxplot has a horizontal axis labeled from 0 to 10 in increments of 1. Vertical line segments are drawn at the following plotted points: 0, 1, 6, 7, 9. A box encloses the vertical line segments at 1, 6, and 7 and horizontal line segments extend outward from both sides of the box to vertical line segments at 0 and 9. All values are approximate. B. 0 3 6 9 A boxplot has a horizontal axis labeled from 0 to 10 in increments of 1. Vertical line segments are drawn at the following plotted points: 0, 3, 6, 7, 9. A box encloses the vertical line segments at 3, 6, and 7 and horizontal line segments extend outward from both sides of the box to vertical line segments at 0 and 9. All values are approximate. C. 0 3 6 9

Respuesta :

*see attachment for the data set given

Answer:

[tex] Q_1 = 2.5 [/tex]

[tex] Q_2 = 5.5 [/tex]

[tex] Q_3 = 8 [/tex]

The box plot is shown in the attachment below.

Step-by-step Explanation:

a. To find Q1, Q2 (median), and Q3, first order the data from the least to the largest. We would have:

0, 1, 1,1, 2, 2, 2, 3, 4, 5, 5, 5, 5, 5, 6, 6, 7, 7, 7, 8, 8, 8, 8, 9, 9, 9, 9, 9

Q2 which is also the median, is the middle value that divides the data set into two equal parts. In the data set given, Q2 is the data value between the 14th and 15th data value. The average of the 14th and the 15th data value would give us Q2.

0, 1, 1,1, 2, 2, 2, 3, 4, 5, 5, 5, 5, [5,Q2, 6], 6, 7, 7, 7, 8, 8, 8, 8, 9, 9, 9, 9, 9

They are 5 and 6. Average = [tex] \frac{5+6}{2} = 5.5 [/tex]

Q1 is the middle value of the lower part of the data set from Q2 down to your left.

0, 1, 1,1, 2, 2, [2, Q1, 3,] 4, 5, 5, 5, 5, 5, Q2, 6, 6, 7, 7, 7, 8, 8, 8, 8, 9, 9, 9, 9, 9

Q1 = average of the 7th and 8th value = [tex] \frac{2+3}{2} = 2.5 [/tex]

Q3 = [tex] \frac{8+8}{2} = 8 [/tex]

0, 1, 1,1, 2, 2, 2, 3, 4, 5, 5, 5, 5, 5,Q2, 6, 6, 7, 7, 7, 8, [8, Q3, 8], 8, 9, 9, 9, 9, 9.

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