Respuesta :
Answer:
3(a). The ship travelled in north is 26.0 km.
(b). The ship travelled in east is 23.4 km.
4(a). The ship travelled in south is -88.61 km.
(b). The ship travelled in west is -179.29 km.
Step-by-step explanation:
Given that,
(3). Distance = 35 km
Angle = 42°
Let distance in north is y km.
We need to calculate the distance
Using vertical component
[tex]y = d\cos\theta[/tex]
Put the value into the formula
[tex]y = 35\cos42[/tex]
[tex]y=26.0\ km[/tex]
Let distance in east is x km
We need to calculate the distance
Using horizontal component
[tex]x =d\sin\theta[/tex]
Put the value into the formula
[tex]x = 35\sin42[/tex]
[tex]x=23.4\ km[/tex]
(4). A ship sails 200 km on a bearing of 243.7°
Let distance in south is y km.
We need to calculate the distance
Using vertical component
[tex]y = d\cos\theta[/tex]
Put the value into the formula
[tex]y = 200\cos243.7[/tex]
[tex]y=-88.61\ km[/tex]
Let distance in west is x km
We need to calculate the distance
Using horizontal component
[tex]x =d\sin\theta[/tex]
Put the value into the formula
[tex]x = 200\sin243.7[/tex]
[tex]x=-179.29\ km[/tex]
Hence, 3(a). The ship travelled in north is 26.0 km.
(b). The ship travelled in east is 23.4 km.
4(a). The ship travelled in south is -88.61 km.
(b). The ship travelled in west is -179.29 km.
