Answer:
[tex]P_2=0.393atm[/tex]
Explanation:
Hello,
In this case, we can use the combined ideal gas law in order to analyze its behavior as a function of changing temperature, volume and pressure:
[tex]\frac{P_1V_1}{T_1} =\frac{P_2V_2}{T_2}[/tex]
Thus, since we know the volume, temperature and pressure at the initial condition, we can compute the final pressure as shown below:
[tex]P_2=\frac{P_1V_1T_2}{T_1V_2} =\frac{1.00atm*225mL*(25+273)K}{(0+273)K*625mL}\\ \\P_2=0.393atm[/tex]
Regards.
