Respuesta :
Answer:
400 N
Explanation:
Pressure is equal on both pistons.
P = P
F / A = F / A
F / (πd²/4) = F / (πd²/4)
F / d² = F / d²
1600 N / (8.0 cm)² = F / (4.0 cm)²
F = 400 N
The force that should be applied to the smaller piston is 400 N.
Given that,
- A hydraulic press has one piston of diameter 4.0 cm and the other piston of diameter 8.0 cm.
- Pressure is equal on both pistons.
Based on the above information, the calculation is as follows:
[tex]1600 N \div (8.0 cm)^2 = F \div (4.0 cm)^2[/tex]
F = 400 N
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