A straight stream of protons passes a given point in space at a rate of 2.5 x 109 protons/s. What magnetic field do they produce 1.5 m from the beam

Respuesta :

Answer:

B = 5.3x10⁻¹⁷ T

Explanation:

The magnetic field can be calculated as follows:

[tex]B = \frac{\mu_{0}I}{2\pi R}[/tex]

Where:

μ₀: is the magnetic permeability = 4πₓ10⁻⁷ H/m

I: is the current          

R: is the distance between the magnetic field and the beam = 1.5 m

The current is:

[tex] I = 2.5 \cdot 10^{9} p/s*1.6 \cdot 10^{-19} C/p = 4.0 \cdot 10^{-10} A [/tex]

Hence, the magnetic field is:            

[tex]B = \frac{\mu_{0}I}{2\pi R} = \frac{4\pi \cdot 10^{-7} H/m*4.0 \cdot 10^{-10} A}{2\pi*1.5 m} = 5.3 \cdot 10^{-17} T[/tex]

Therefore, the magnetic field is 5.3x10⁻¹⁷ T.

I hope it helps you!  

The magnetic field will be "[tex]5.3\times 10^{-17} \ T[/tex]".

Magnetic field:

According to the question,

Magnetic permeability, [tex]\mu_0 = 4 \pi\times 10^{-7} \ H/m[/tex]

Distance between magnetic field and beam, R = 1.5 m

The current (I) will be:

= [tex]2.5\times 10^9\times 1.6\times 10^{-19}[/tex]

= [tex]4.0\times 10^{-10} \ A[/tex]

hence,

The magnetic field (B) be:

= [tex]\frac{\mu_0 I}{2 \pi R}[/tex]

By substituting the values,

= [tex]\frac{4 \pi\times 10^{-7}\times 4.0\times 10^{-10}}{2 \pi\times 1.5}[/tex]

= [tex]5.3\times 10^{-17} \ T[/tex]

Thus the response above is appropriate.

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