Answer:
55.7 N
Explanation:
The density of aluminum is 2710 kg/m³. So its volume is:
V = (9 kg) / (2710 kg/m³)
V = 0.00332 m³
The apparent weight is the actual weight minus the buoyant force.
N = mg − B
N = mg − ρVg
N = g (m − ρV)
N = (9.8 m/s²) (9 kg − (1000 kg/m³) (0.0332 m³))
N = 55.7 N
