Answer:[tex]\rho=7.87g/mL[/tex]
Explanation:
Hello,
In this case, we are analyzing a problem in which the Archimedes principle is considered, thus, as the volume of the metal rod is determined by the difference between the mass of the water and the mass of the water and the rod:
[tex]V_{rod}=15.00mL-10.00mL=5.00mL[/tex]
In such a way, the density turns out:
[tex]\rho =\frac{m_{rod}}{V_{rod}}=\frac{39.35g}{5.00mL} \\ \\\rho=7.87g/mL[/tex]
Regards.
