Answer/Step-by-step explanation:
Segments AB and AC are both radii of the circle with center A. All radii of a circle are always equal, tgerefire,:
[tex] AB = AC [/tex]
Segments AB and BC are both radii of the circle with center B. All radii of a circle are always equal, therefore:
[tex] AB = BC [/tex]
Thus,
[tex] AB = AC = BC [/tex]
∆ABC has sides AB, AC, and BC, which are all equal (equal radii).
Therefore, ∆ABC is an equilateral triangle.
An equilateral triangle has 3 equal sides.
