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16-08-2020
Mathematics

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logx - logx-1^2=2log(x-1) what is the value of x

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16-08-2020

Answer:

Step-by-step explanation:

[tex]logx -log(x-1)^2= 2 log(x-1)[/tex]

[tex]logx-2log(x-1) = 2log(x-1)[/tex]

[tex]logx=log(x-1)^4[/tex]

[tex]x=(x-1)^4[/tex]

[tex]x^4-4x^3+6x^2+1=0[/tex]

solve this equation

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