Respuesta :
Answer:
3.48 atm
Explanation:
The first step is to determine the number moles of sulfuric acid. To do this find the molar mass of sulfuric acid.
Molar Mass of H2SO4 = (1 g/mol*2) + (32 g/mol) + (16 g/mol * 4) = 98 g/mol
Then divide the mass of sulfuric acid by the molar mass of the sulfuric acid to get the number of moles of sulfuric acid.
(10 g)/(98 g/mol) = 0.10204 mol
Then use the molar ratios to determine the moles of gas produced. In this case all of the ratios are 1 to 1 meaning that 0.10204 mol of H2SO4 produces 0.10204 mol of H2O and 0.10204 mol of SO3. That means that 0.2041 moles of gas are produced as a result of the reaction.
The next thing to do is to convert the temperature to Kelvin since gas equations need Kelvin. To do this add 273.15.
350 degrees C + 273 = 623.15 K
Now the PV=nRT can be used and when solving for pressure the equation can be written P=nRT/V.
P = pressure and is the unknown
V = volume and is 3.00 L
n = moles of gas and is 0.2041 mol
R = gas constant and is 0.08205 L atm/mol K
T = temperature and is 623.15 K
P = (0.2041 mol * 0.08205 L atm/mol K * 623.15 K) / 3.00 L
P = 3.4785 atm which is 3.48 atm when rounded to three significant figures
I hope this helps. Let me know if anything is unclear.
The total pressure of the container has been 3.48 atm.
In the decomposition of 10 grams of sulfuric acid, the moles of sulfuric acid has been:
Moles = [tex]\rm \dfrac{weight}{molecular\;weight}[/tex]
Moles of sulfuric acid = [tex]\rm \dfrac{10\;g}{98\;g/mol}[/tex]
Moles of sulfuric acid = 0.1024 moles.
The balanced chemical equation for the reaction results in the formation of 1 mole of water and 1 mole of [tex]\rm SO_3[/tex]. Thus, the decomposition of 1 mole of gas produces 2 moles of the product.
The moles of the product by decomposition of 0.1024 moles of sulfuric acid has been:
1 mole sulfuric acid = 2 moles product
0.1024 moles sulfuric acid = 0.2048 moles product.
From the ideal gas equation:
PV = nRT
P = pressure
V = volume = 3 L
n = moles = 0.2048 moles
R = constant = 0.08205 L atm/mol K
T = temperature = 623.15 K
Substituting the values:
Pressure × 3 L = 0.2048 mol × 0.08205 L atm/mol K × 623.15 K
Pressure = 3.4785 atm.
The pressure of the system has been 3.48 atm.
For more information about the pressure of the system, refer to the link:
https://brainly.com/question/908756
