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A two digit number is chosen at random. Find the probality that the number is a perfect square​

Respuesta :

Answer:

[tex]\Large \boxed{\frac{1}{15} }[/tex]

Step-by-step explanation:

The two-digit perfect squares are 16, 25, 36, 49, 64, 81.

There are 6 numbers that are two-digit perfect squares.

There are a total of 90 numbers that have two-digits.

P(two-digit perfect square) = [tex]\frac{6}{90} =\frac{1}{15}[/tex]

The  Probability  that the number is a perfect square out of two-digit number is chosen at random is [tex]\frac{1}{15}[/tex] .

What is the probability?

Probability is a branch of mathematics that deals with the occurrence of a random event.

For example, when a coin is tossed in the air, the possible outcomes are Head and Tail.

Probability formula :

Probability(Event) = Favorable Outcomes/Total Outcomes

According to the question

A two digit number is chosen at random.

Total number of two digit number are from 10 to 99

i.e

=99-10+1 = 90

or Total Outcomes = 90

Total of perfect square​ of two-digits are: 16,25,36,49,64,81

Total number of perfect square​ of two-digits = 6  

or Favorable Outcomes = 6

Now , The Probability  that the number is a perfect square

Probability(Event) = Favorable Outcomes/Total Outcomes

Probability(Event) = [tex]\frac{6}{90}[/tex]

Probability(Event) = [tex]\frac{1}{15}[/tex]

Hence, the  Probability  that the number is a perfect square out of two-digit number is [tex]\frac{1}{15}[/tex] .

To know more about Probability   here :

https://brainly.com/question/11234923

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