Respuesta :
Answer:
5 cm.
Step-by-step explanation:
Let the lengths of the other 2 sides be 13-1 = 12 and x cm.
Then by Pythagoras:
13^2 = 12^2 + x^2
x^2 = 13^2 - 12^2
x^2 = 169 - 144 = 25
x = √25
x = 5 cm.
Step-by-step explanation:
Hey, there!!
As per your question,
There is a Right angled triangle, whose hypotenuse is 13 cm, one side is (13-1)=12 cm.
another side = ?
Let ABC be a Right angled triangle, taking angle "theta" as a refrence angle.
Hypotenuse (h)= 13 cm.
base ( b) = x
perpendicular (p)= 12cm.
By Pythagoras relation we get,
[tex]b = \sqrt{ {h}^{2} - {p}^{2} } [/tex]
[tex]b = \sqrt{ {13}^{2} - {12}^{2} } [/tex]
[tex]b = \sqrt{169 - 144} [/tex]
Therefore, base is 5 cm. Or the third side is 5 cm.
Hope it helps...
