Answer:
[tex]1.33\times 10^{-8} N[/tex]
Explanation:
According to the given scenario, the computation of force between them is shown below:-
As we know that
[tex]\mu = 4\pi\times 10^{-7}[/tex]
The force between two current carrying wires will be
[tex]F = \frac{\mu_oI_1I_2L}{2\pi r}[/tex]
[tex]= \frac{4\pi\times 10^{-7} (1 A) (1 A) (1.0 m)}{2\pi (1.5m)}[/tex]
[tex]= 1.33\times 10^{-7} N[/tex]
[tex]= 1.33\times 10^{-8} N[/tex]
Therefore for computing the force between two wires we simply applied the above formula.
So, the force between two wires carrying 1 A current [tex]= 1.33\times 10^{-8} N[/tex].
