zinnia30
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50pts + brainliest pls helllppppppppppppppppppppp
find the equation of straight line passing through (1,-1) and (3,-5) pls help im in online class and i have to answer pls helllllllllllppppppppppppppp

Respuesta :

Answer:

Equation y = -2x -3

Step-by-step explanation:

(1,-1) (3,-5)

Slope = -5-(-1) / 3-1 = -5+1/2 = -4/2 = -2

y = mx + K

-1 = -2(1) + k

-1 = -2 + k

k = 1

Equation y = -2x+1

Answer:

Step-by-step explanation:

slope=(y2-y1)/(x2-x1)=(-5-(-1))/(3-1)=(-5+1)/2=-4/2=-2

y-y1=m(x-x1)

y-(-1)=-2(x-1)

y+1=-2(x-1)

y+1=-2x+2

y=-2x+2-1

y=-2x+1

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