Answer:
Area of the rhombus=840
Step-by-step explanation:
Perimeter of a rhombus=4a
148=4a
a=148/4
=37
a=37
The diagonal divides the rhombus into two congruent triangle,
Each congruent triangle= 37 x 37 x 24.
To get the area of the rhombus, we will find the area of one of the congruent triangle, then multiply by 2.
Using Hero's formula to find the area of a triangle, we will use the three sides
Area = √[ s(s-a)(s-b)(s-c) ]
where a, b, and c are the lengths of the three sides: a = 37, b = 37, and c = 24.
s=semiperimeter
s = (a + b + c) / 2
= (37 + 37 + 24)/2
= 98/2
= 49.
s=49
Substitute all the values into the formula
Area = √[ s(s-a)(s-b)(s-c) ]
= √[ 49(49-37)(49-37)(49-24) ]
=√[ 49(12)(12)(25) ]
=√[49(3600)]
=√(176,400)
= 420
Area of one triangle=420
Area of a rhombus=Area of one triangle×2
=420×2
=840
