Please answer this ASAP. Maribel is building rectangular pens for her dogs, as shown below. She will fence the entire rectangular area with 78m of fencing. What dimensions enclose the total maximum area. Show your work?

Please answer this ASAP Maribel is building rectangular pens for her dogs as shown below She will fence the entire rectangular area with 78m of fencing What dim class=

Respuesta :

Answer: w = 13 m, L = 19.5 m

Step-by-step explanation:

P = 3w + 2L

     3w + 2L = 78

              2L = 78 - 3w

                [tex]L=\dfrac{78-3w}{2}[/tex]

                                       

A = w · L

[tex]A=w\bigg(\dfrac{78-3w}{2}\bigg)\\\\\\A=\bigg(\dfrac{78w-3w^2}{2}\bigg)\\\\\\A=39w-\dfrac{3}{2}w^2\\\\\\0=-\dfrac{3}{2}w^2+39w-A[/tex]

    a=-3/2   b=39

[tex]\text{Axis of Symmetry}:w=\dfrac{-b}{2a}=\dfrac{-39}{2(-\frac{3}{2})}=\dfrac{-39}{-3}=\large\boxed{13}[/tex]

[tex]\text{Maximum}:L=\dfrac{78-3w}{2}=\dfrac{78-3(13)}{2}=\dfrac{78-39}{2}=\dfrac{39}{2}=\large\boxed{19.5}[/tex]

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