Answer:
a). B = 24 yd²
b). h = 8 yd
c). S.A. = 240 yd²
Step-by-step explanation:
Area of the triangular base B = [tex]\frac{1}{2}(\text{Base of the right triangle})(\text{height of the base triangle})[/tex]
= [tex]\frac{1}{2}(8)(6)[/tex]
= 24 yd²
Height of the prism 'h' = distance between the triangular bases
= 8 yd
Perimeter of the triangular base = leg 1 + leg 2 + hypotenuse
= 8 + 6 + 10 = 24 yd
Surface area = 2B + Ph
= (2×24) + (24×8)
= 48 + 192
= 240 square yds
