Answer:
P(AB) = 837/9100
Step-by-step explanation:
The given parameters are;
The number of marbles in the bag = 100 marbles
The number of red marbles = 27
The number of green marbles = 42
The number of blue marbles = 100 - 27 - 42 = 31
The probability, A of drawing a blue marble = 31/100
The probability,B of drawing a red marble after a blue marble has been taken without replacement = 27/91
The probability P(AB) = 31/100× 27/91 = 837/9100
The probability that Eric randomly draws two marbles without replacing the first one where the first one is a blue marble and the second marble is a red marble is 837/9100.
