Jenna drives on average 46 miles per day with a standard deviation of 5.3 miles per day. Suppose Jenna's miles driven per day are normally distributed. Let X = the number of miles driven in a given day. Then X - N(46, 5.3). If necessary, round to three decimal places.
Provide your answer below:
Suppose Jenna drives 41 miles on Monday. The Z-score when x - 41 is______ . The mean is________ This z-score tells you that x = 41 is________ standard deviations to the left of the mean.

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Answer:

Suppose Jenna drives 41 miles on Monday. The Z-score when x - 41 is    [tex]-0.943[/tex].   The mean is  [tex]46[/tex]  This z-score tells you that x = 41 is  [tex]0.94[/tex]  standard deviations to the left of the mean.

Step-by-step explanation:

From the question we are told that

  The  mean is  [tex]\= x = 46\ miles / day[/tex]

  The standard deviation is  [tex]\sigma = 5.3 \ miles \ per \ day[/tex]

   The  value of =  41

Generally the z-score is mathematically represented as

        [tex]z = \frac{x-\= x}{\sigma }[/tex]

substituting values  

         [tex]z = \frac{41-46}{5.3}[/tex]

          [tex]z = - 0.943[/tex]

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