Answer:
99% confidence interval for the proportion of married young adults aged 18-29.
(0.1779 , 0.2287)
Step-by-step explanation:
Step(i):-
Given sample size 'n' = 964
Given data a random sample of 964 young adults aged 18-29, it was found that 196 of them were married
sample proportion
[tex]p^{-} = \frac{196}{964} = 0.2033[/tex]
Step(ii):-
99% confidence interval for the proportion of married young adults aged 18-29.
[tex](p^{-} - Z_{0.05} \sqrt{\frac{p^{-}(1-p^{-} ) }{n} } ,p^{-} +Z_{0.05} \sqrt{\frac{p^{-}(1-p^{-} ) }{n} })[/tex]
[tex](0.2033 -1.96 \sqrt{\frac{0.2033(1-0.2033 ) }{964} } ,0.2033 +1.96\sqrt{\frac{0.2033(1-0.2033 ) }{964} })[/tex]
(0.2033 - 0.02540 , 0.2033 +0.02540)
(0.1779 , 0.2287)
Conclusion:-
99% confidence interval for the proportion of married young adults aged 18-29.
(0.1779 , 0.2287)
