Complete Question
The complete question is shown on the first uploaded image
Answer:
The induced emf is [tex]\epsilon = B * l * v[/tex]
Step-by-step explanation:
Now assume that the coil is shaped as a rectangle with length [tex]l[/tex] and width b
This implies that the area of the coil is [tex]A= l * b[/tex]
Now when it enter into the uniform magnetic field the magnetic flux due to its movement as stated in the question is mathematically represented as
[tex]\phi = BA[/tex]
=> [tex]\phi = B (l* b )[/tex]
Now the induced emf is mathematically represented as
[tex]\epsilon = \frac{d\phi}{dt}[/tex]
=> [tex]\epsilon = B * l [\frac{db}{dt} ][/tex]
The [tex]l[/tex] is constant because as it glides to and from the magnetic field it is displaced along the horizontal plane while along the vertical plane it is constant
Here [tex]\frac{db}{dt} = v[/tex]
Where is the velocity the glide (i.e the coil)
So
[tex]\epsilon = B * l * v[/tex]
Based on the information given, it should be noted that the induced emf will be e = Blv.
According to Farday's law, the magnitude of the emf that's induced in a circuit will be proportional to the rate of change of the magnetic flux.
In this case, since the coil is rectangular shaped, the area will be the length multiplied by the width. When it enters the uniform magnetic field, the magnetic flux will be:
= B(l × b)
The induced emf will now be:
= B × l × v
= Blv
In conclusion, induced emf will be e = Blv.
Learn more about emf on:
https://brainly.com/question/4721624
