Answer:
[tex]\frac{\sqrt{17} + \sqrt{2} }{\sqrt{17} + \sqrt{2}}[/tex]
Step-by-step explanation:
To rationalize the denominator, we usually multiply and divide by the conjugate.
The conjugate of [tex]\sqrt{17} - \sqrt{2}[/tex] is [tex]\sqrt{17} + \sqrt{2}[/tex] (The sign usually of the conjugate is opposite)
So, we're going to multiply it by [tex]\frac{\sqrt{17} + \sqrt{2} }{\sqrt{17} + \sqrt{2}}[/tex]
