Answer:
(a) 0.635
(b) 0.498
Step-by-step explanation:
(a) The probability distribution is calculated using the cumulative distribution function of the Poisson as follows;
CDF = [tex]F(x)=e^{-\lambda t}\sum_{i = 0}^{\left | x \right |}\dfrac{\lambda t^{i}}{i!}[/tex]
For x = three we have;
CDF = 0.781
For x = one we have;
CDF = 0.1465
Therefore, the probability that between one and three inclusive = 0.781 - 0.1465 = 0.635
(b) For x = 2 we have;
CDF = 0.4395
For x = one we have;
CDF = 0.9378
Therefore, the probability that between one and three inclusive = 0.9378- 0.4395= 0.498
