Answer:
B) It must be a weak acid.
Explanation:
If HA is a strong acid
[tex]HA\rightleftharpoons H^++A^-[/tex]
Now the pH value can be written as follows
[tex]pH=-log[H^+]\\pH=-log(5\times 10^{-2})\\pH=2\times log5\\pH=1.4[/tex]
But given that acid HA has 2.3 pH value.
Therefore we can say that HA is weak acid.
Thus the answer will be option (B).
B) It must be a weak acid.
