Answer:
From the analysis W1=W2.
they are directly related
Step-by-step explanation:
the work-done in stretching a spring can be expressed as
[tex]W=\frac{1}{2}kx^2[/tex]
where k= spring constant
x= change on length of spring
Hence for W1
Given data
x= 34-24= 10 cm
solving in terms of k we have
[tex]W=\frac{1}{2}k*10^2\\\W=\frac{1}{2}k*100\\\W=50k[/tex]
Hence for W2
Given data
x= 44-34= 10 cm
solving in terms of k we have
[tex]W=\frac{1}{2}k*10^2\\\ W=\frac{1}{2}k*100\\\ W=50k[/tex]
