Answer:
Explanation:
Rotational kinetic energy of flywheel
= 1/2 Iω² where I is moment of inertia , ω is angular velocity
for wheel I = 1/2 m R² where m is mass and R is radius of flywheel
Putting the values
I = 1/2 x 370 x .5²
= 46.25 kg m²
ω = 2πn where n is frequency of revolution per second
ω = 2 x 3.14 x 540 = 3391.2
Rotational kinetic energy = .5 x 46.25 x 3391.2²
= 265.94 x 10⁶ J
If this energy is transferred to a car of mass 1600kg , velocity acquired by it be v , then
kinetic energy of car = rotational kinetic energy of flywheel
= 1/2 m v ² = 265.94 x 10⁶
.5 x 1600 v² = 265.94 x 10⁶
v² = 33.24 x 10⁴
v = 5.76 x 10²
= 576 m /s
