Which linear inequality is represented by the graph? y ≤ 2x + 4 y ≤ one-halfx + 3 y ≥ One-halfx + 3 y ≥ 2x + 3

Answer:
Option B.
Step-by-step explanation:
From the given graph it is clear that the related line passes through the points (0,3) and (2,4).
So, the equation of related line is
[tex]y-y_1=\dfrac{y_2-y_1}{x_2-x_1}(x-x_1)[/tex]
[tex]y-3=\dfrac{4-3}{2-0}(x-0)[/tex]
[tex]y-3=\dfrac{1}{2}x[/tex]
Add 3 on both sides, we get
[tex]y=\dfrac{1}{2}x+3[/tex]
The related line is a solid line and shaded portion lies below the line. So, the sign of inequality must be ≤.
[tex]y\leq \dfrac{1}{2}x+3[/tex]
Therefore, the correct option is B.