Answer:
[tex] \boxed{\sf Width \ of \ the \ rectangle = 3ab} [/tex]
Given:
Length of the rectangle = 4b cm
Area of the rectangle = 12ab² square cm
To Find:
Width of the rectangle
Step-by-step explanation:
[tex] \sf \implies Area \: of \: the \: rectangle = Length \times Width \\ \\ \sf \implies 12 a{b}^{2} = 4b \times Width \\ \\ \sf \implies Width \times 4b = 12a {b}^{2} \\ \\ \sf Divide \ both \ side \ by \ 4b: \\ \sf \implies Width \times \frac{4b}{4b} = \frac{12a {b}^{2} }{4b} \\ \\ \sf \frac{4b}{4b} = 1: \\ \sf \implies Width = \frac{12 a{b}^{2} }{4b} \\ \\ \sf \implies Width = \frac{3ab \times \cancel{4b}}{ \cancel{4b}} \\ \\ \sf \implies Width = 3ab[/tex]
