Answer:
See below.
Step-by-step explanation:
[tex](5x^2y^3)^0\div(-2x^{-3}y^5)^{-2}[/tex]
First, note that everything to the zeroth power is 1. Thus:
[tex]=1\div(-2x^{-3}y^5)^{-2}=\frac{1}{(-2x^{-3}y^5)^{-2}}[/tex]
Distribute using Power of a Power property:
[tex]=\frac{1}{(-2)^{-2}(x^{-3})^{-2}(y^5)^{-2})}[/tex]
Make the exponents positive by putting them to the numerator:
[tex]=\frac{(-2)^2(x^{-3})^2(y^5)^2}{1}[/tex]
[tex]=\frac{4x^{-6}y^{10}}{1}[/tex]
Make the exponent positive by this time putting it to the denominator:
[tex]=\frac{4y^{10}}{x^6}[/tex]
