Answer:
3x√5 + 6√(10x) + 5√(3x) + 10√6
Step-by-step explanation:
[tex](\sqrt{3x}+\sqrt{5})(\sqrt{15x}+2\sqrt{30})=\sqrt{3x}(\sqrt{15x}+2\sqrt{30})+\sqrt{5}(\sqrt{15x}+2\sqrt{30})\\\\=\sqrt{45x^2}+2\sqrt{90x}+\sqrt{75x}+2\sqrt{150}\\\\=\sqrt{5(3x)^2}+2\sqrt{10x(3)^2}+\sqrt{3x(5)^2}+2\sqrt{6(5)^2}\\\\=\boxed{3x\sqrt{5}+6\sqrt{10x}+5\sqrt{3x}+10\sqrt{6}}[/tex]
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The applicable rules of roots are ...
(√a)(√b) = √(ab)
√(ab²) = b√a
